**Dynamics Chapter 8. Simple Harmonic Motion and Vibeology
Recommended Reading: 【Physics】 Physics Table of Contents
1. Vibeology
2. Type 1. Simple Harmonic Motion
3. Type 2. Damped Oscillation
4. Type 3. Forced Oscillation
a. Simple Harmonic Motion Experiment
1. Vibeology
⑴ Definition: The mechanical motion of an object exhibiting wave-like properties
2. Type 1. Simple Harmonic Motion** (Simple Undamped Oscillation, Simple Harmonic Motion)
Figure 1. Simple Harmonic Motion Diagram
⑴ Overview: Constant period
⑵ Cause: When restoring force and inertia act together in a system, simple harmonic motion occurs
① Restoring force: A force proportional to the displacement change
② Typically obtained through differential equations like y” + Ky = 0, K > 0
○ The term y” arises from F = ma
○ The Ky term appears because the restoring force is proportional to displacement change
③ Total energy due to restoring force
○ E = K + U
○ E = ½ kA², where A is the amplitude (maximum displacement)
④ Potential energy due to restoring force
○ Relationship between potential and force: F = -∇U
○ Since restoring force F ∝ x, U ∝ x²
○ Potential energy due to restoring force is lowest at the equilibrium point and increases as displacement changes
○ Stability classification
○ Stable equilibrium: U” > 0 (convex downward), U’ (x=0) = 0
○ Unstable equilibrium: U” < 0 (convex upward), U’ (x=0) = 0
⑤ Nonlinear effect
○ When the displacement from equilibrium is large enough that the restoring force is no longer proportional to displacement
○ Leads to modified simple harmonic motion
⑶ System Definition
① Solution to the differential equation
② Frequency Domain Conversion
⑷ Example 1. Simple Harmonic Motion Under a Spring
① Definition: A mass undergoing horizontal oscillation on a massless spring
② Elastic Force(Elastic Force): A force that restores an object to its original state due to atomic repulsion
○ Elasticity: The tendency of an object to return to its original shape when deformed
○ Elastic body: A body with elasticity (e.g., springs, rods, rubber used in keyboards)
○ Elastic force: A measure of an elastic body’s restoring force
○ Elastic limit: The point beyond which an elastic body cannot return to its original state
○ Hooke’s Law: The extension of a spring is proportional to the applied force
○ Equation: F ∝ x (deformation length) → F = -kx (where k is the elastic constant)
○ The negative sign indicates the force is in the opposite direction of elongation
○ Elastic Constant (Spring Constant): The force required to extend a spring by 1 m
○ Coil spring
○ Overlapping plate spring
○ Compliance: The inverse of the spring constant
○ Change in spring constant for series connection: Springs connected in series stretch more easily, reducing the spring constant
○ Change in spring constant for parallel connection: Springs connected in parallel require more force, increasing the spring constant
③ Simple Harmonic Motion by Elastic Force: Establishing equations using external force = restoring force = elastic force, then solving the second-order differential equation
④ Conclusion: The period T of a spring depends only on mass m and elastic constant k
⑸ Example 2. Simple Pendulum
① A mass suspended by a massless string oscillating with small amplitude
② The period T of the pendulum depends only on the string length ℓ
③ Physical pendulum: When a rigid body undergoes pendulum motion about a pivot in a gravitational field
④ Here, I is the moment of inertia about the pivot, and h is the distance from the pivot to the center of mass
⑹ Example 3. Simple Harmonic Motion of a Mass Suspended on a Spring in Gravity
(Neglecting Spring Mass)
① Given a mass m and the gravity-induced extension x (which may be negative),
○ Φ: Initial phase
○ xm: Amplitude (maximum displacement)
② Initial Condition: Assuming v = x = 0 at t = 0
③ Tip 1. The center of oscillation is where elastic force and gravity balance
④ Tip 2. The amplitude is determined by the initial conditions: The distance from the initial position to the oscillation center
⑤ Tip 3. The period: Independent of initial speed, extension length, and gravitational acceleration
⑺ Example 4. Simple Harmonic Motion of a Mass Suspended on a Spring in Gravity (Considering Spring Mass) (ref)
Figure 2. Considering the Mass of the Spring
① Condition 1. Mass of the bob M, mass of the spring m, spring constant k, spring length L, distance from attachment point L
② Condition 2. The spring is uniform, L ≫ extended length x
③ Under force equilibrium, the extended length x(y) at a point y from the top is
④ This equation implies a varying spring constant along the position, treating the spring mass as distributed
⑤ Finding the average spring constant
⑥ For m ≪ M, using the Taylor series expansion of ln(1 + x),
⑦ The approximate period formula follows, assuming (1 + x)-1 ≒ 1 - x
⑧ A more precise calculation is highly complex
⑻ Example 5. Pendulum Wave
① Definition: 15 pendulums moving in and out of phase over a 60-second cycle, creating a wave-like motion (ref)
② Design: Fine-tuning the pendulum lengths so that within 60 seconds, the 1st to 15th pendulums oscillate 51 to 65 times, respectively
⑼ Example 6. Exact Solution for Pendulum Motion
① Premises
○ Situation: Free undamped simple pendulum motion
○ Governing equation
○ Initial conditions
○ Approximation of the governing equation (θ ≪ 1)
○ Approximate general solution (θ ≪ 1)
○ Approximate particular solution (θ ≪ 1)
② Exact Solution
○ Transformation
○ Trigonometric relations
○ 1st substitution
○ 2nd substitution: ω0 comes from the governing equation, independent of angular frequency
○ Limitation for z
○ Exact solution for τ
③ Jacobi Elliptic Function
○ Elliptic integral
○ Definition of Jacobi elliptic function sn
○ Expression of τ using elliptic integral
○ Period formula involving K(k)
○ Expression of sn in terms of τ
○ Conclusion
⑽ Example 7. Convergence of the Exact Solution of Pendulum Motion under Air Resistance
(ref)
① Problem: Let u(t) be the solution of the following differential equation. Show that the functions u(t) and u’(t) are bounded for t > 0. Also, determine the limit limt→∞ u(t).
② Solution:
First, define v(t) := u’(t). Then, given that (u(0), v(0)) = (1, 0), the following equation holds:
Thus, we obtain: -et ≤ et v(t) ’ = et sin u(t) ≤ et.
By integrating, we get: v ≤ 1 - e-t ≤ 1. Next, define w(t) := 2 cos u(t) + (v(t))2.
Then, we compute: w’ = -2u’ sin u + 2vv’ = 2v sin u + 2v(-v + sin u) = -2v2.
Since w(t) is a decreasing function, it follows that: cos u(t) ≤ cos u(t) + (v(t))2 / 2 ≤ cos u(0) + (v(0))2 / 2 = cos 1.
Using the continuity of u(t), we obtain: 1 ≤ u(t) ≤ 2π-1
Since w(t) is a decreasing function and satisfies w(t) ≥ -2, the limit limt→∞ w(t) = β exists, and we have:
Now, assume β > 2.
Then, for any ε > 0, there exists some t0 such that for all t > t0, cos u(t) > β / 2 - ε, v(t) < ε
If we assume β / 2 - ε > -1 for sufficiently small ε > 0, then two possible cases arise:
Case 1: This contradicts the boundedness of v for sufficiently small ε > 0.
Case 2: Similar contradiction follows.
Thus, we conclude that: limt→∞ cos u(t) = -1 and limt→∞ u(t) = π.
⑾ Example 8. Demonstrating Circular Motion as Simple Harmonic Motion
⑿ Example 9. LC Circuit
Figure 3. Oscillation in an LC Circuit
Figure 4. Analysis of an LC Circuit
⒀ Example 10. Atomic Oscillations
3. Type 2. Damped Oscillation
Figure 5. Damped Oscillation Diagram
⑴ Governing Equation
⑵ Frequency Domain Conversion
⑶ Introduction of β and Classification of Damped Oscillation
① β² - ω₀² > 0: Overdamped (heavy damping)
② β² - ω₀² = 0: Critically damped
③ β² - ω₀² < 0: Underdamped (light damping)
⑷ Generally, β < ω₀ holds
4. Type 3. Forced Oscillation
Figure 6. Forced Oscillation Diagram
⑴ Governing Equation
⑵ When fe is a trigonometric function
① Oscillation = Natural Vibration + Steady-State Vibration
② Natural Vibration = Homogeneous Solution = Complementary Solution = Transient Solution
○ Due to e-βt, it converges to 0 over time
③ Steady-State Vibration = Particular Solution
○ Typically, only the particular solution is of interest
○ Assumed as complex harmonic motion
○ ω ≪ ω₀
○ ω = ω₀
○ ω ≫ ω₀
5. Mechanical Impedance
⑴ Definition
① Defined as complex driving force ÷ complex velocity at the driving point
② Concept of force magnitude required to obtain velocity
⑵ SDOF (Single Degree of Freedom) System
① Zm: Inherent property of material, used to predict response
② Rm: Mechanical resistance, representing energy loss
③ Xm: Mechanical reactance, representing energy storage
④ If impedance is known, the system response can be determined
⑶ When ω ≪ ω₀: Zm* = -js / ω
① Spring-like (stiffness-like) impedance
② Negative imaginary component
③ Inversely proportional to frequency
⑷ When ω = ω₀: Zm* = Rm
⑸ When ω ≫ ω₀: Zm* = jωm
① Mass-like impedance
② Positive imaginary component
③ Linearly proportional to frequency
⑹ Imaginary Impedance: When Rm = 0
① Force and velocity are out of phase
② No power is required to drive the system
○ Since Rm = 0, no energy is dissipated
6. Mechanical Resonance
⑴ Definition: The frequency at which the reactance component Xm becomes zero
⑵ The vibration frequency at which the imaginary part of impedance is zero
7. Superposition
Figure 7. Superposition Diagram
⑴ Assumption 1. Small Amplitude Response
⑵ Assumption 2. The System is Linear
⑶ Mathematical Formulation
Input: 2019.04.09 08:59
Modified: 2023.10.07 17:04